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Leetcode 121. 买卖股票的最佳时机(DAY 26) ---- 动态规划学习期
阅读量:207 次
发布时间:2019-02-28

本文共 637 字,大约阅读时间需要 2 分钟。

原题题目

在这里插入图片描述



代码实现(首刷自解) 一遍遍历 但为什么效率极低

int maxProfit(int* prices, int pricesSize){       int i,min = INT_MAX,max = -1,profit = -1;    for(i=0;i
max) { max = prices[i]; if(max - min > profit) profit = max - min; } } } return profit;}

代码实现(二刷C++ 整理股票博客)

class Solution {   public:    int maxProfit(vector
& prices) { int size = prices.size(),minbuy = prices[0],maxsold = 0; for(const auto& num:prices) { maxsold = max(maxsold,num-minbuy); minbuy = min(minbuy,num); } return maxsold; }};

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